17x^2+18x-8=0

Solution for 17x^2+18x-8=0 equation:

17x^2+18x-8=0

a = 17; b = 18; c = -8;
Δ = b2-4ac
Δ = 182-4·17·(-8)
Δ = 868
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{868}=\sqrt{4*217}=\sqrt{4}*\sqrt{217}=2\sqrt{217}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(18)-2\sqrt{217}}{2*17}=\frac{-18-2\sqrt{217}}{34}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(18)+2\sqrt{217}}{2*17}=\frac{-18+2\sqrt{217}}{34}
$